f(m+3)=2m^2-2m+1

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Solution for f(m+3)=2m^2-2m+1 equation: 


Simplifying
f(m + 3) = 2m2 + -2m + 1

Reorder the terms:
f(3 + m) = 2m2 + -2m + 1
(3 * f + m * f) = 2m2 + -2m + 1
(3f + fm) = 2m2 + -2m + 1

Reorder the terms:
3f + fm = 1 + -2m + 2m2

Solving
3f + fm = 1 + -2m + 2m2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
-1 + 3f + fm + 2m + -2m2 = 1 + -2m + 2m2 + -1 + 2m + -2m2

Reorder the terms:
-1 + 3f + fm + 2m + -2m2 = 1 + -1 + -2m + 2m + 2m2 + -2m2

Combine like terms: 1 + -1 = 0
-1 + 3f + fm + 2m + -2m2 = 0 + -2m + 2m + 2m2 + -2m2
-1 + 3f + fm + 2m + -2m2 = -2m + 2m + 2m2 + -2m2

Combine like terms: -2m + 2m = 0
-1 + 3f + fm + 2m + -2m2 = 0 + 2m2 + -2m2
-1 + 3f + fm + 2m + -2m2 = 2m2 + -2m2

Combine like terms: 2m2 + -2m2 = 0
-1 + 3f + fm + 2m + -2m2 = 0

The solution to this equation could not be determined.

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